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Posted by: laifai

Original: 4/7/2009 6:17 AM
Views: 39
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2 eProps!2 eProps! 2 eProps from:
kkllau
death_knight_arthas
Devil_hkct

Tuesday, April 07, 2009

 曾猶豫過無數次...究竟自己適唔適合做一個programmer

一直以來都好似ok, 都叫搞得掂...

今次真係搞唔掂......

我真係諗唔掂平衡運算...........

好痛苦

看似明白

結果都係比concurrency既問題打沉

我真係唔明...點解明明d位置係割好曬 計0岩曬

佢就係出一個錯既答案比我

點解block內可以輕鬆sync0岩曬

多過一個block就永世都sync唔到

我唔明

我真係唔明


依一年, 究竟係我唔識點樣去問人點做

定係真係無人比我問



做左成年...
寫少少野都寫唔到...
廢柴......
 Posted 4/7/2009 6:17 AM - 39 Views - 6 eProps - 4 comments

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4 Comments

Visit kkllau's Xanga Site!
冷靜落唻
冇0野難得到我地
係時候迫出你0既真材實料

無論答案0岩唔0岩
FYP 總有辦法做得掂
記住希望在明天
Posted 4/7/2009 7:40 AM by kkllau - reply

Visit kkllau's Xanga Site!

remember the LS spirit!
Never Say Die

Posted 4/7/2009 7:43 AM by kkllau - reply

Visit death_knight_arthas's Xanga Site!

block外面?
如果係sync既問題,以fpga黎講,inside成粒fpga,main clocking region都切四份,一個大既clocking region再斬四個localize既region,個clock signal route遠d route近d,已經會有clock skew。
data path係place and route都有影響,有d path route出黎delay長d,有d短d,呢度除左影響個max frequency,亦會影響係same clock edge裏面,sample到個data會係old data (clock trigger快過data到)定係new data(data快過clock trigger到),正常黎講都係會latch返個old data。
最簡單係兩個pipe既shift chain。
process (arst,clk)
begin
    if (arst='1') then
        r1<='0';
        r2<='0';
    elsif (rising_edge(clk)) then
        r1<=din;
        r2<=r1;
    end if;
end process;
r1去r2果度有delay,所以din唔會係一下clock edge sync起左之後直出r2。
重有d signal既edge係dead zone,係果d位sample一定錯。
你block與block之跟做sync,有無check過個sync signal靚唔靚?重有d電線d noice又會另個signal樣衰左,sync得無咁好。如果你話sync有問題,我覺得係hardware問題,同埋要留意下呢d minor野,唔係logic同program可以解決到。
其實我既留言係咪off左topic?=.=

Posted 4/8/2009 3:23 AM by death_knight_arthas - reply

Visit Devil_hkct's Xanga Site!
Don't Give UP~~
you Are My ProUD~***ha
Posted 4/9/2009 3:27 AM by Devil_hkct - reply


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